3n^2+603n-7668=0

Solution for 3n^2+603n-7668=0 equation:

3n^2+603n-7668=0

a = 3; b = 603; c = -7668;
Δ = b2-4ac
Δ = 6032-4·3·(-7668)
Δ = 455625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{455625}=675$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(603)-675}{2*3}=\frac{-1278}{6}
=-213
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(603)+675}{2*3}=\frac{72}{6}
=12
$